## Tags » Bit

#### Reverse bits in an integer

Say this integer has M bits

def reverse_bits(n, M):
N = 1 << M
r = n # will store the bit-revevrsed pattern
for i in xrange(M):
n >> 1
r << 1
r |= n&1 # Give LSB of n to r
r &= N-1 # N-1 is a mask, will clear all bits more significant than N-1
return r

# A improved version
def reverse(n, M):
N = 1 << M
count = M -1
r = n

while n != 0:
n >> 1
r << 1
r |= n&1
count -= 1
r << count
r &= N-1
return r

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Problem Statement

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Problem Statement

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OJ Problem