Let p(u) denote the number of paths start from u. For a node u, p(u) is equal to the summation of all p(v)+1, which there is a edge from u to v. We can compute the p value reverse topologically. … more →
Exercise Lover:// wrote 1 month ago: Gimp is an image editing program. It has support on on the most moder operating systems including … more →
morris wrote 2 months ago: The Israelis are very very clever. But … They brutalise the helpless, and are shocked to s … more →
hacktek wrote 3 months ago: Rumor has it (since it hasn’t really happened to me or anybody i know, same as with 2.40) that … more →
Gerald wrote 3 months ago: Sony disappoints Playstation 3 owners. Again. First, Playstation Home was delayed. Then, the in-game … more →
playstationyeio wrote 3 months ago: The official word on the PlayStation blog goes like this: This update improves the playback quality … more →
playstation3xuxe wrote 3 months ago: It seems Sony has sneaked out another firmware update for the PS3 but before you rush to download it … more →
gdogg16 wrote 6 months ago: HDR photo from a photo shoot of a Volvo 242 Turbo I did while at the Carlisle Import Kit Replica sho … more →
Josh Kimball wrote 7 months ago: *Music magazines are not doing well at all. I guess everyone is reading the Daily Swarm. [ypulse] *S … more →
yuhanlyu wrote 1 year ago: Let p(u) denote the number of paths start from u. For a node u, p(u) is equal to the summation of al … more →
yuhanlyu wrote 1 year ago: Solution 1: For each node v, create a node v’. Remove out-edges of v from v then add to v … more →
yuhanlyu wrote 1 year ago: Because the last node has only in-edges, no out-edges. … more →
farrukh: copywriter & journalist wrote 1 year ago: For me as an advertising copywriter in Dubai, UAE, it’s good to benchmark with ads that hav … more →