Solution 1: For each vertex v, construct DFS tree T rooted from v. Check whether T has forward or cross edge. If every T has no forward or cross edge, then G is singly connected. Time complexity is … more →
Exercise Loversapphir3 wrote 3 months ago: How a bit of business came from a little (un)pleasure . . . Many of us It’s Pop! readers are f … more →
sapphir3 wrote 3 months ago: The difficulties of a new band breaking into the established scene. Continuation … Books, Inst … more →
sapphir3 wrote 3 months ago: The difficulties of a new band breaking into the established scene. Continuation … the next st … more →
William Kapeles wrote 8 months ago: The prices shown here are the wholesale cost to us. Add approximately $50.00 for a regular delivere … more →
pscyclone wrote 9 months ago: I’ve mentioned in a couple of other posts (here, here, and here) my opinion about the political … more →
William Kapeles wrote 9 months ago: Hello everyone, just wanted to get the word out about a great receiver for you AR-15 enthusiasts. … more →
William Kapeles wrote 1 year ago: My brother just informed me that the Republik of Kalifornia has decreed that its subjects are no lon … more →
tellinghistory wrote 1 year ago: The current space exploration program led by NASA is shifting into a transition from the human expl … more →
tellinghistory wrote 1 year ago: The current space exploration program led by NASA is shifting into a transition from the human expl … more →
William Kapeles wrote 1 year ago: This is an oldie, but a goodie and bears repeating on here! WHY SOME MEN FAVOR HANDGUNS OVER WOMEN … more →
William Kapeles wrote 1 year ago: I wanted to give everyone an update on the ammodata.com website we’re putting together. It … more →
William Kapeles wrote 1 year ago: We are in the process of developing a new loaded ammunition product and we need a catchy name. Plea … more →
yuhanlyu wrote 1 year ago: Solution 1: For each vertex v, construct DFS tree T rooted from v. Check whether T has forward or cr … more →
yuhanlyu wrote 1 year ago: Let F be the DFS forest, if u and v are in the same tree, then u and v are in the same connected com … more →
yuhanlyu wrote 1 year ago: Let G=(V,E), V={u,v,w}, E={<v,u>,<u,w>}. … more →
yuhanlyu wrote 1 year ago: The same as exercises 22.3-7. … more →
yuhanlyu wrote 1 year ago: Let G=(V,E). V = {u, v, w}, E={<w,u>, <w,v>, <u,w>}. The dfs tree = {<w,u>, … more →
yuhanlyu wrote 1 year ago: Modify the DFS-Visit(u) line 4~7 as follows. Push u into stack S While S is not empty u = pop … more →